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5x^2=2880
We move all terms to the left:
5x^2-(2880)=0
a = 5; b = 0; c = -2880;
Δ = b2-4ac
Δ = 02-4·5·(-2880)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*5}=\frac{-240}{10} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*5}=\frac{240}{10} =24 $
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